MATH SOLVE

3 months ago

Q:
# Day 4: As a landscaper, one of your clients wants a rectangular garden in which the length is five feetmore than twice the width. The perimeter of the garden is 82 feet. In square feet, what is the area ofthe garden?

Accepted Solution

A:

Answer:The Area of Rectangular Garden is 1044 feet² Step-by-step explanation:According to question The perimeter of the garden = 82 ftLet the length be L ftThe width be W ftNow as per question L = 5 + ( 2× W )∵ Perimeter of Rectangle = 2 × ( Length + Width )Or , Perimeter of Rectangle = 2 × ( L+ W )Or, 82 = 2 × ( L+ W )Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]Or, 82 = 2 × ( 5 +3W )Or, 41 = 5 + 3WOr, 41 - 5 = 3WSo, 3W= 36∴ W = [tex]\frac{36}{3}[/tex] = 12 feetI.e Width = 12 feetAnd L = 5 + ( 2× W )Or, Length = 5 + 24 = 29 feet Now The Area of Rectangle = Length × widthSo, The Area of Rectangle = 29 ft × 36 ftThe Area of Rectangle is 1044 feet²Hence The Area of Rectangular Garden is 1044 feet² Answer